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Experiment 10: auto Scope, Part IV

The Question: If a name has two different meanings (i.e., declarations): one in an "outer" block and one in a nested "inner" block, and the name is accessed within the outer block, which meaning is accessed?

Hypothesis: Review the rules of scope, and then construct a hypothesis.



The Experiment: If we display the value of arg1 following the inner block (following its redeclaration), we can get an answer to our question:

   int main()
   {
      int arg1;
      arg1 = -1;
      ...
      {
         char arg1 = 'A';
      }
      cout << '\n' << arg1 << endl;
   }

Observation: Translate your source program. What is displayed ?





Conclusions: Review the rules of scope and explain what happened.

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